Article 16
Expansion of Hyperbolic Functions.

For this purpose take Maclaurin’s Theorem,

f(u) = f(0) + uf(0) + 1 2!u2f(0) + 1 3!u3f(0) + ,

and put

f(u) = sinhu,f(u) = coshu,f(u) = sinhu,,

then

f(0) = sinh0 = 0,f(0) = cosh0 = 1,;

hence

sinhu = u + 1 3!u3 + 1 5!u5 + ;  (27)

and similarly, or by differentiation,

coshu = 1 + 1 2!u2 + 1 4!u4 + .  (28)

By means of these series the numerical values of sinhu,coshu, can be computed and tabulated for successive values of the independent variable u. They are convergent for all values of u, because the ratio of the nth term to the preceding is in the first case u2 (2n 1)(2n 2), and in the second case u2 (2n 2)(2n 3), both of which ratios can be made less than unity by taking n large enough, no matter what value u has. Lagrange’s remainder shows equivalence of function and series.

From these series the following can be obtained by division:

tanhu = u 1 3u3 + 2 15u5 + 17 315u7 + , sechu = 1 1 2u2 + 5 24u4 61 720u6 + , ucothu = 1 + 1 3u2 1 45u4 + 2 945u6 , ucschu = 1 1 6u2 + 7 360u4 31 15120u6 + . (29)

These four developments are seldom used, as there is no observable law in the coefficients, and as the functions tanhu,sechu,cothu,cschu, can be found directly from the previously computed values of coshu,sinhu.

Prob. 36.
Show that these six developments can be adapted to the circular functions by changing the alternate signs.