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Article 15
Derivatives of Anti-hyperbolic Functions.
(
a
)
d
(
sinh
−
1
x
)
d
x
=
1
x
2
+
1
,
(
b
)
d
(
cosh
−
1
x
)
d
x
=
1
x
2
−
1
,
(
c
)
d
(
tanh
−
1
x
)
d
x
=
1
1
−
x
2
x
<
1
,
(
d
)
d
(
coth
−
1
x
)
d
x
=
1
1
−
x
2
x
>
1
,
(
e
)
d
(
sech
−
1
x
)
d
x
=
−
1
x
1
−
x
2
,
(
f
)
d
(
csch
−
1
x
)
d
x
=
−
1
x
x
2
+
1
,
(26)
(a)
Let
u
=
sinh
−
1
x
, then
x
=
sinh
u
,
d
x
=
cosh
u
d
u
=
1
+
sinh
2
u
=
1
+
x
2
d
u
,
d
u
=
d
x
1
+
x
2
.
(b)
Similar to (a).
(c)
Let
u
=
tanh
−
1
x
, then
x
=
tanh
u
,
d
x
=
sech
2
u
d
u
=
(
1
−
tanh
2
u
)
d
u
=
(
1
−
x
2
)
d
u
,
d
u
=
d
x
1
−
x
2
.
(d)
Similar to (c).
(e)
d
(
sech
−
1
x
)
d
x
=
d
d
x
cosh
−
1
1
x
=
−
1
x
2
1
x
2
−
1
1
2
=
−
1
x
1
−
x
2
.
(f)
Similar to (e).
Prob. 31.
Prove
d
(
sin
−
1
x
)
d
x
=
1
1
−
x
2
,
d
(
cos
−
1
x
)
d
x
=
−
1
1
−
x
2
,
d
(
tan
−
1
x
)
d
x
=
1
1
+
x
2
,
d
(
cot
−
1
x
)
d
x
=
−
1
1
+
x
2
.
Prob. 32.
Prove
d
sinh
−
1
x
a
=
d
x
x
2
+
a
2
,
d
cosh
−
1
x
a
=
d
x
x
2
−
a
2
,
d
tanh
−
1
x
a
=
a
d
x
a
2
−
x
2
x
<
a
,
d
coth
−
1
x
a
=
−
a
d
x
x
2
−
a
2
x
>
a
.
Prob. 33.
Find
d
(
sech
−
1
x
)
independently of
cosh
−
1
x
.
Prob. 34.
When
tanh
−
1
x
is real, prove that
coth
−
1
x
is imaginary, and conversely; except when
x
=
1
.
Prob. 35.
Evaluate
sinh
−
1
x
log
x
,
cosh
−
1
x
log
x
when
x
=
∞
.
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