Article 23
Derivatives of Gudermanian and Inverse.

Let

v = gdu,u = gd1v,  then secv = coshu, secvtanvdv = sinhudu, secvdv = du,  therefore d(gd1v) = secvdv.  (48)        Again, dv = cosvdu = sechudu,  therefore d(gdu) = sechudu.  (49)
Prob. 61.
Differentiate:

y = sinhu gdu, y = sinv + gd1v, y = tanhusechu + gdu, y = tanvsecv + gd1v.
Prob. 62.
Writing the “elliptic integral of the first kind” in the form
u =0φ dφ 1 κ2 sin 2 φ,

κ being called the modulus, and φ the amplitude; that is,

φ = amu,(mod.κ),

show that, in the special case when κ = 1,

u = gd1φ, amu = gdu, sinamu = tanhu, cosamu = sechu, tanamu = sinhu;

and that thus the elliptic functions sinamu, etc., degenerate into the hyperbolic functions, when the modulus is unity.3